2 JULY 1983, Page 32

Solution to 611: Chain letters 10 E 2L. 6 01 5 4A

.221 .2.1A1) R n A N ILELANTIALEA 'bCKEATEFICAMI,CE

SITICI IIS X A L T EIBIA w

IES.TAAIRrA SIRN

PEOINI1X+'HANKSTA,STE 2ANE OIDESOIK EI 0 TRIAEIL R ELE0 T 1HILE I S L E 9 ,../ TIE

H -7 0 NI NI 0 R RIC A R NIAIC E U AIYI RI 4 , 11% T T A R FLSrA M NLE.0 I C RLIERRIER3CREUA 4i1OR XOREMENIT,AIL IC

The chain of increasing anagrams is formed by 7A, 35D, 33D, 12D, 13A, 23D, 21D, 19D and IA.

Winner: Mrs J. M. Nash, Meadowsweet, Southam Lane, Southam, Cheltenham.