27 DECEMBER 1968, page 29

Chess No. 419

PHILIDOR Solution to no. 418 (Schumer): (a) Kt – B 6 mate. (b) I R– B 7, R any; 2 R mates accordingly. (c) I R – B 3, P R; 2 P – Kt 8 = Q, P – Kt 5: 3 Q – Q 5. (d) I Kt – B 3. P......

No. 531: The Winners

Trevor Grove reports: Competitors were in- vited to compose an intelligible piece of prose around ten given words, chosen from the open- ing passages of a well-known book. They......